Returns its first argument multiplied by 2 raised to the power of its second argument; that is, x(2n) .
#include <math.h> double ldexp (double x, int n);
x(2n) | The first argument multiplied by 2 raised to the power of the second argument. |
0 | Indicates underflow; errno is set to ERANGE. |
HUGE_VAL | Indicates overflow; errno is set to ERANGE. |